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Find the zeroes of the polynomial $x^{2} + x - p (p + 1)$

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- p, - (p + 1)

p, (- p + 1)

- p, (- p + 1)

p, - (p + 1)

answer is D.

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Detailed Solution

x^{2} + x - p (p + 1)

$x^{2} + p x + x - p x - p (p + 1)$

$x^{2} + x (p + 1) - p x - p (p + 1)$

$x^{2} - p x + x (p + 1) - p (p + 1)$

$x (x - p) + (p + 1) (x - p)$

$(x - p) (x + p + 1)$

$x - p = 0 (o r) x + p + 1 = 0$

$x = p (o r) x = - (p + 1)$

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