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Q.

Find the zeros of the following quadratic polynomials and verify the relationship between the zeros and their coefficients:


g(x)=ax2+1-xa2+1


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a

x=-a and x=1-a

b

x=a and x=1a

c

x=2a and x=12a

d

x=3a and x=13a 

answer is B.

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Detailed Solution

Given quadratic polynomials
gx=ax2+1-xa2+1
We put the value of function equal to zero
gx=0
ax2+1-xa2+1=0
ax2+a-a2x-x=0
ax2-a2x-x+a=0
axx-a-1x-a=0
x-aax-1=0
x-a=0 and ax-1=0 then
x=a and x=1/a
Now Using this formula,
Sum of zeros =- coefficient of x coefficient of x2
Put the value in the formula
a+1a=--a2+1a
a2+1a=a2+1a
We calculate Product of roots
= constant  coefficient of x2
a×1a=aa
1=1
Verified the relation between zeros and their coefficients.
Hence, the zeros of each of gx=ax2+1-xa2+1 is x=a and x=1/a.
Option 2 is correct.
 
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