Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

Find the zeros of the following quadratic polynomials and verify the relationship between the zeros and their coefficients:


g(x)=ax2+1-xa2+1


see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

x=-a and x=1-a

b

x=a and x=1a

c

x=2a and x=12a

d

x=3a and x=13a 

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Given quadratic polynomials
gx=ax2+1-xa2+1
We put the value of function equal to zero
gx=0
ax2+1-xa2+1=0
ax2+a-a2x-x=0
ax2-a2x-x+a=0
axx-a-1x-a=0
x-aax-1=0
x-a=0 and ax-1=0 then
x=a and x=1/a
Now Using this formula,
Sum of zeros =- coefficient of x coefficient of x2
Put the value in the formula
a+1a=--a2+1a
a2+1a=a2+1a
We calculate Product of roots
= constant  coefficient of x2
a×1a=aa
1=1
Verified the relation between zeros and their coefficients.
Hence, the zeros of each of gx=ax2+1-xa2+1 is x=a and x=1/a.
Option 2 is correct.
 
Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon