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Find the zeros of the polynomial ${6 x}^{2} - 3 - 7 x$

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\frac{3}{2}

- \frac{1}{3}

- \frac{3}{2}, - \frac{1}{3}

\frac{3}{2}, \frac{1}{3}

- \frac{3}{2}, \frac{1}{3}

answer is A.

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Detailed Solution

Given polynomial is

{6 x}^{2} - 3 - 7 x

We can write this as

{6 x}^{2} - 3 - 7 x = 0

Or,

{6 x}^{2} - 9 x + 2 x - 3 = 0

Or, 3x(2x – 3) + 1(2x – 3) = 0
Or, (2x – 3)(3x + 1) = 0
2x – 3 = 0
Or,

x = \frac{3}{2}

And 3x+1=0
Or,

x = - \frac{1}{3}

Hence,

\frac{3}{2}, - \frac{1}{3}

are the two zeroes of the given polynomial

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