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Q.

Find three consecutive integers whose sum is 366.


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a

121, 122 and 123

b

120, 121 and 122

c

170, 171 and 172

d

118, 119 and 120 

answer is A.

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Detailed Solution

Let the first number be x then two consecutive numbers will be, x+1 and x+2, now we get the equation as,
x+x+1+x+2=366
Or, 3x+3=366
Or, 3x=366−3
Or, x=3633
Or, x=121
As the first number of the three consecutive number x=121 so the next two numbers are x+1=121+1 = 122 and x+2=121+2 = 123.
The answer we get is
121+122+123=366
The answer is 121, 122 and 123.
 
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Find three consecutive integers whose sum is 366.