Find three consecutives even numbers such that the sum of the first and last term exceeds the second one by 10.

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6,10,12

8, 10, 12

4, 12, 14

6, 12, 16

answer is B.

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Detailed Solution

Concept- We begin by attempting to define three successive even integers in their general form. We then attempt to apply the supplied condition and get a linear equation from it. We solve the equation and obtain the value of the middle term in order to determine the other components.
Let's begin by considering the three consecutive even numbers. We first take the middle even number as

.
The previous and the next even numbers will be

and

.
We have been given that the sum of the first and last term exceeds the second one by 10 which means the sum of

and

exceeds the 2k by 10
Sum of

and

will be

. This exceeds

by 10 .
This gives us

. Solving the equation, we get

$Question Image$ So, the middle term is 10 . The other two terms are

and