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Q.

Find three irrational numbers between  0.202002000200002 and 0.20303003000300003.



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a

0.20201001007100001 , 0.202020020002,  0.202030930030003,   0.203040030003 

b

0.20201001008100001 , 0.202020020002,  0.292030030030003,   0.203030830003

c

0.20201001000100001 , 0.202020020002,  0.202030030030003,   0.203030030003

d

0.20201001000500001 , 0.202020620002,  0.202030030039003,   0.203037030003 

answer is C.

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Detailed Solution

Concept:  We know that there is infinite irrational number between the given irrational numbers. So, now we will go for optional verification. The irrational number which is greater than   0.20202002000200002 and less than 0.203003000300003 are the correct option.
Irrational number given in question is:
0.202002000200002 and 0.203003000300003
As we know, there are infinite irrational numbers that exist between two irrational numbers.
0.2020100100010001 Here we can see clearly 0.20201001000100001 is greater 0.202002000200002  and less than 0.203003000300003.
(b)) 0.202020020002  Here we can clearly see 0.202020020002 is greater than 0.20202002000200002 and is less than 0.203003000300003.
(C) 0.202030030003
Here we can see clearly 0.202030030003 is greater than 0.202002000200002 and less than 0.203003000300003.
(d)0.203030030003
clearly ,0.203030030003 is greater than 0.202002000200002 and  0.203003000300003.
Hence, option 3 is incorrect  
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