Find total number of'Ions which form paramagnetic complex trrespectrva of nature of ligand in octahedral geometry. $(\mathrm{C}.\mathrm{N}.=6)$

${\mathrm{Se}}^{+3},{\mathrm{Ti}}^{3+},{\mathrm{Cr}}^{+3},{\mathrm{Pt}}^{+4},{\mathrm{Ni}}^{+2},{\mathrm{Co}}^{+3},{\mathrm{Fe}}^{+3}$

The number of ion which form the paramagnetic complex are,

${\mathrm{Cr}}^{3+},{\mathrm{Ni}}^{2+},{\mathrm{Fe}}^{3+},{\mathrm{Ti}}^{3+}$

Here, the nature of ligand in octahedral geometry does not matters.

Hence correct answer is 0004.