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Q.

Find unit vector perpendicular to the plane of a=2i^-2j^+k^ and b=i^+2j^+2k^.

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a

23i^+23j^13k^

b

23i^+13j^+23k^

c

23i^13j^+23k^

d

23i^13j^23k^

answer is C.

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Detailed Solution

a×b=|a||b|n^ 
n^=a×b|a|.|b|=|i^j^k^221122|(4+4+11+4+4) 
=i^(42)j^(41)+k^(4+2)9 
=69i^39j^+69k^=23i^13j^+23k^   

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