Find $\frac{6}{9}-\frac{1}{3}$

The fractions $\frac{6}{9}$ and $\frac{1}{3}$ have different denominators. In order to subtract them, we need to make the denominators equal.

LCM of 9 and 3 is 9.
Convert the fractions to have a denominator of 9.
$\frac{6}{9}=\frac{6\times 1}{9\times 1}=\frac{6}{9}$,
$\frac{1}{3}=\frac{1\times 3}{3\times 3}=\frac{3}{9}$

Now, $\frac{6}{9}-\frac{1}{3}=\frac{6}{9}-\frac{3}{9}$

$=\frac{6-3}{9}=\frac{3}{9}$

$=\frac{1}{3}$
Therefore, $\frac{6}{9}-\frac{1}{3}=\frac{1}{3}$ .