$\mathrm{Find} \mathrm{the} \mathrm{difference} \mathrm{between} \mathrm{the} \mathrm{sum} \mathrm{and} \mathrm{product} \mathrm{of} 2\frac{1}{2} \mathrm{and} 1\frac{3}{5}.$

$\begin{array}{rcl} & & \mathrm{Given}:\\ & & \mathrm{Fractions} 2\frac{1}{2} \mathrm{and} 1\frac{3}{5}.\\ & & \\ & & \mathrm{To} \mathrm{calculate} :\\ & & \mathrm{Difference} \mathrm{between} \mathrm{sum} \mathrm{and} \mathrm{product} \mathrm{of} \mathrm{these} \mathrm{fractions}.\\ & & \\ & & \mathrm{Calculations}:\\ & & \mathrm{Fractions} 2\frac{1}{2} \mathrm{and} 1\frac{3}{5} \mathrm{are} \frac{ 5}{2} \mathrm{and} \frac{8}{5 } \mathrm{respectively}.\\ & & \mathrm{Their} \mathrm{sum} \mathrm{is} \\ & =& >\frac{5}{2}+\frac{8}{5}=\frac{41}{10}\\ & & \mathrm{Their} \mathrm{product} \mathrm{is}\\ & =& >\frac{5}{2}\times \frac{8}{5}=4=\frac{40}{10}\\ & & \mathrm{So}, \mathrm{sum} -\mathrm{product} \mathrm{will} \mathrm{be}\\ & =& >\frac{41}{10}-\frac{40}{10}\\ & =& >\frac{1}{10}\\ & & \mathrm{Hence} \mathrm{option} \mathrm{C} \mathrm{is} \mathrm{correct}.\\ & & \end{array}$