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Q.

First Balmer line in H-spectrum is 660 nm. The wavelength of second Balmer line is :

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a

889.2 nm

b

388.9 nm

c

6a2.7 nm

d

488.9 nm

answer is D.

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Detailed Solution

$\frac{1}{λ_{1}} = \frac{1}{660} = R_{H} [\frac{1}{2^{2}} - \frac{1}{3^{2}}] = R_{H} \times \frac{5}{36} \frac{1}{λ_{2}} = R_{H} [\frac{1}{2^{2}} - \frac{1}{4^{2}}] = R_{H} \times \frac{3}{16} ∴ λ_{2} = 660 \times \frac{5}{36} \times \frac{16}{3} = \frac{4}{27} \times 660 = 488 .9 nm$

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