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Q.

First ionisation enthalpy of Magnesium is 738 kJ/mole. The change in enthalpy for the process  Mgg  Mg2+(g) will be

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a

900 kJ

b

2188 kJ

c

1071 kJ

d

1475 kJ

answer is B.

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Detailed Solution

Given

I.P1 of Mg = + 738 kJ/mole ;

I.P2 of Mg must be > 738 kJ/mole ;

Thus sum of I.P1 and I.P2 will be > 1476 kJ

Thus

Mgg Mg2+g, H >1476 kJ ;

By inspection, the only option which is greater than 1476 kJ is Option (2)

 

 

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