Five coins are tossed 3200 times. The expected number of times we get exactly two heads is

$\mathrm{X}=\mathrm{getting} \mathrm{a} \mathrm{head} \mathrm{when} \mathrm{a} \mathrm{coin} \mathrm{is} \mathrm{tossed}$

$p=q=\frac{1}{2},n=5\Rightarrow P\left(X=2\right)={ }^5{C}_2{\left(\frac{1}{2}\right)}^5=\frac{10}{32}=\frac{5}{16}$

$3200. P(x = 2)=3200\left(\frac{5}{16}\right)=1000$