Five digit numbers divisible by 3 is formed using 0, 1, 2, 3, 4 and 5 without repetition. Total number of such numbers are

$\text{1+2+3+4+5=15 }$  

The no of arrangements using 1,2, 3,4,5 is $\text{5!}$

$\text{0+1+2+4+5=12}$

The no of arrangement using 0,1,2,3,4,5 is $5!-4!$

$\therefore$ $5!+5!-4!=216$