Five forces F→1,F→2,F→3,F→4 and F→5, are acting on a particle of mass 2.0 kg so that it is moving with 4 m/s2 in east direction. If F→1 force is removed, then the acceleration becomes 7 m/s2 in north, then the acceleration of the block if only F→1 is acting will be

F→1+F→2+F→3+F→4+F→5=2(4i^) .......(i)and F→2+F→3+F→4+F→5=2(7j^) ........(ii) From (i) and (ii), F→1=8i^−14j^a→1=F→1m=4i^−7j^⇒ a1=16+49=65m/s2

Five forces F→1,F→2,F→3,F→4 and F→5, are acting on a particle of mass 2.0 kg so that it is moving with 4 m/s2 in east direction. If F→1 force is removed, then the acceleration becomes 7 m/s2 in north, then the acceleration of the block if only F→1 is acting will be

F→1+F→2+F→3+F→4+F→5=2(4i^) .......(i)and F→2+F→3+F→4+F→5=2(7j^) ........(ii) From (i) and (ii), F→1=8i^−14j^a→1=F→1m=4i^−7j^⇒ a1=16+49=65m/s2

AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

Five forces ${\vec{F}}_{1}, {\vec{F}}_{2}, {\vec{F}}_{3}, {\vec{F}}_{4} and {\vec{F}}_{5}$ , are acting on a particle of mass 2.0 kg so that it is moving with 4 m/s² in east direction. If ${\vec{F}}_{1}$ force is removed, then the acceleration becomes 7 m/s² in north, then the acceleration of the block if only ${\vec{F}}_{1}$ is acting will be

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

$16 m / s^{2}$

$\sqrt{65} m / s^{2}$

$\sqrt{260} m / s^{2}$

$\sqrt{33} m / s^{2}$

answer is B.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\begin{array}{l} {\vec{F}}_{1} + {\vec{F}}_{2} + {\vec{F}}_{3} + {\vec{F}}_{4} + {\vec{F}}_{5} = 2 (4 \hat{i}) . . . . . . . (i) \\ and {\vec{F}}_{2} + {\vec{F}}_{3} + {\vec{F}}_{4} + {\vec{F}}_{5} = 2 (7 \hat{j}) . . . . . . . . (i i) \end{array}$

$From (i) and (ii), {\vec{F}}_{1} = 8 \hat{i} - 14 \hat{j}$

$\begin{array}{l} {\vec{a}}_{1} = \frac{{\vec{F}}_{1}}{m} = 4 \hat{i} - 7 \hat{j} \\ \Rightarrow a_{1} = \sqrt{16 + 49} = \sqrt{65} m / s^{2} \end{array}$