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Q.

Five forces F1F2F3F4 and F5 are acting on a particle of mass 2.0 kg so that it is moving with 4 m/s2 in east direction. If F1 force is removed, then the acceleration becomes 7 m/s2 in north, then the acceleration of the block if only F1 is acting will be:

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a

16 m/s2

b

65  m/s2

c

33 m/s2

d

260 m/s2

answer is .

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Detailed Solution

F1+F2 + F3+F4 + F5  = 2(4i^)         -------(i)

and F2+F3+F4+F5 = 2(7j^)      ------(ii)

From (i) and (ii), F1 = 8i^ - 14j^

a1 = F1m = 4i^ -7 j^

  a1 = 16+49 = 65 m/s2

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