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Q.

Five identical cells each of internal resistance $1 Ω$ and emf 5V are connected in series and in parallel with an external resistance 'R' . For what value of 'R', current in series and parallel combination will remain the same?

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Detailed Solution

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$i_{r} = \frac{25}{5 + R}$

In parallel, $E_{e q} = E = 5 V$

$r_{e q} = \frac{r}{5} = \frac{1}{5} Ω$

$i_{2} = \frac{5}{R + \frac{1}{5}}$

Put $i_{1} = i_{2}$

We get $4 R = 4 \Rightarrow R = 1 Ω$

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