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Five resistance $R_{1}, R_{2}, R_{3}, R_{4} and R_{5}$ connected in a circuit are $10 ohms, 40 ohms, 30 ohms, 20 ohms and 60 ohms$ in parallel having $12 volts$ potential difference. What will be the total current flowing in the circuit?

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1.7 A

2.1 A

2.7 A

3.1 A

answer is C.

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Detailed Solution

Five resistance

R_{1}, R_{2}, R_{3}, R_{4} and R_{5}

connected in a circuit are

10 ohms, 40 ohms, 30 ohms, 20 ohms and 60 ohms

in parallel having

12 volts

potential difference.

2.7 A

will be the total current flowing in the circuit.
Given that, Potential Difference,

V = 12 volts

Resistance in Parallel,

\frac{1}{R} = \frac{1}{R_{1}} + \frac{1}{R_{2}} + \frac{1}{R_{3}} + \frac{1}{R_{4}} + \frac{1}{R_{5}}

Now, Resistance,

\frac{1}{R} = \frac{1}{10} + \frac{1}{40} + \frac{1}{30} + \frac{1}{20} + \frac{1}{60}

= \frac{9}{40}

Now, we can write

R = \frac{40}{9}

= 4.4 Ω

We know that According to Ohm’s law

V = I R

\Rightarrow 12 = I \times 4.4

⸫

I = 2.7 A

Hence, the total current flowing in the circuit is

2.7 amperes

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