Q.

Five years ago, Nuri was thrice as old as Sonu. Ten years later, Nuri will be twice as old as Sonu. How old are Nuri and Sonu? 


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a

50, 20

b

40, 30

c

50, 70

d

10, 20 

answer is A.

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Detailed Solution

Let age of nuri is x and age of sony is y
Five years ago
Age of Nuri = x – 5 years
Age of Sony = y – 5 years
Nuri was thrice as old as Sonu
x- 5  =  3(y – 5)
x – 5  =  35 – 15
x – 3y  =  -15  + 5
x – 3 y  = - 10                        ………..(1)
Ten years later,
Age of Nuri  = x + 10
Age of Sonu = y + 10
Nuri will be twice as old as Sonu.
x+ 10 = 2(y+10)
x + 10  = 2y + 20
x – 2y  = 10                           ………..(2)
x – 3 y  = - 10                        ………..(1)
Subtracting equation (1) from equation (2)  we get
y = 20
Plug this value in equation first we get
x−3×20 = −10
x = 60 – 10
x = 50
Hence age of Nuri = 50 years and age of Sonu = 20 years
 
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