Fluorine exhibits only –1 oxidation state, while iodine exhibits oxidation states of –1, +1, +3, +5 and +7. This is due to

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Fluorine being a gas

non-availability of d-orbitals in iodine

iodine is a solid

available d-orbitals in iodine

answer is B.

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Detailed Solution

Due to absence of d-orbitals, F can not expand its valency but I can expand its valency (as shown in the figure) and therefore, exhibits variable oxidation states.

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