Following are the steps for the construction of the ∆ABC in which AB = 6 cm, ∠A = 30°, and B = ∠60°and the construction of another ∆AB’C’ whose sides are $\frac{4}{3}$ times the corresponding sides of ∆ABC.

Steps of construction:

• Draw an ∆ABC with side AB = 6 cm, ∠A = 30°, and ∠B = 60°.
• Draw a ray AX making an acute angle with AB on the opposite side of point C.

Choose the next step of the construction from the given options.

Steps of construction:

• Draw an ∆ABC with side AB = 6 cm, ∠A = 30°, and ∠B = 60°.
• Draw a ray AX making an acute angle with AB on the opposite side of point C.
• Locate equal distance points A₁, A₂ and A₃ on AX. 
• Join A₃B
• Make 4^th point A₄ on AX Such that to A₂A₃ = A₃A₄.
• Draw a line through A₄ parallel to A₃B intersecting extended AB at B’.
• Draw a line parallel to BC intersecting ray AY at C’.

Hence, ∆AB’C’ is the required triangle.