Following are the steps of construction of a triangle with sides 5 cm, 6 cm, and 7 cm and then another triangle whose sides are $\frac{7}{5}$ of the corresponding sides of the first triangle

Construction Procedure:-

1. Draw a line segment AB =5 cm.

2. Take A and B as the center, and draw the arcs of radius 6 cm and 7 cm, respectively.

3. These arcs will intersect each other at point C, and therefore, ΔABC is the required triangle with the length of sides as 5 cm, 6 cm, and 7 cm, respectively.

 

Choose the correct next step for the construction from the given options.

Construction Procedure:-

1. Draw a line segment AB =5 cm.

2. Take A and B as the center, and draw the arcs of radius 6 cm and 7 cm, respectively.

3. These arcs will intersect each other at point C, and therefore, ΔABC is the required triangle with the length of sides as 5 cm, 6 cm, and 7 cm, respectively.

4. Draw a ray AX which makes an acute angle with the line segment AB on the opposite side of vertex C.

5. Locate the 7 points, such as A₁, A₂, A₃, A₄, A₅, A₆, A₇ (as 7 is greater between 5 and 7), on line AX such that it becomes AA₁ = A₁A₂ = A₂A₃ = A₃A₄ = A₄A₅ = A₅A₆ = A₆A₇

6. Join the points BA₅ and draw a line from A₇ to BA_5, which is parallel to the line BA₅ where it intersects the extended line segment AB at point B’.

7. Now, draw a line from B’ to the extended line segment AC at C’, which is parallel to the line BC, and it intersects to make a triangle.

8. Therefore, ΔAB’C’ is the required triangle.