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Q.

Following equilibria are established in three different equal volume containers.

Reaction I: X2(g)+YO2(g)X2O(g)+YO(g); Keq  at  2000K=4
Reaction II: 2X2O(g)2X2(g)+O2(g); Keq at 2000K=5×1010
Reaction III: 2YO(g)+O2(g)2YO2(g); Keq at 1000K=2.5×1022
Which of the following statements is/are CORRECT?

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a

In reaction I, equilibrium amount of YO(g) can be increased by increasing the  volume of container at constant temperature

b

In reaction III, equilibrium amount of YO(g) can be increased by decreasing the  pressure at constant temperature.

c

In reaction II, addition of Helium gas at constant volume and temperature increases  the equilibrium amount of O2(g).

d

In reaction III, the forward reaction must be exothermic.

answer is B, D.

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Detailed Solution

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(iii)=2×(i)1×(ii)

K3 at 2000K=(14)2×(15×1010)1=1.25×108<(K3at  1000K)

Hence, value of K3 is decreasing with increase in temperature. Forward reaction is exothermic.

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