Following is given the equation of a stationary wave (all in SI units)  y = (0.06)sin(2$\mathrm{\pi }$x) cos(5$\mathrm{\pi }$t)
Match the following

	Table 1		Table-2
A)	Amplitude of constituent wave	P)	0.06
B)	Position of node at x =……m	q)	0.5
C)	Position of antinode at x =….m	R)	0.25
D)	Amplitude at x = 3/4m	S)	0.03

	A	B	C	D
1)	S	R	Q	P
2)	R	S	P	Q
3)	S	R	P	Q
4)	R	S	Q	P

(A) Amplitude of constituent wave
= maximum amplitude of stationary wave/2
= 0.03m
(B) 0.06sin2$\mathrm{\pi }$x
At node, A_x = 0
2$\mathrm{\pi }$x = 0, $\mathrm{\pi }$, 2$\mathrm{\pi }$...... 
$\Rightarrow$x = 0, 0.5, 1.0, ...(in m)
(C) In between the nodes, there are antinodes. Therefore there are antinodes at x = 0.25m, 0.75m…. 
(D) At x = 3/4m or 0.75m, we are getting antinode or A_x = 0.06m