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Fom the following data prepare a continuous grouped frequency distribution and find the size of class intervals.

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Class size = 14

Class size =10

Class size = 12

Class size = 16

answer is D.

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Detailed Solution

The given data is,
Question Image

Difference between two mid points is 25-15 =10

\Rightarrow

Width of class interval is 10.
Let a be the lower limit of the first class interval
So the upper limit will be a + 10
Mid class of the first class interval is 5
We know that, Mid value =

\frac{(Lower limit + Upper limit)}{2}

\Rightarrow

\frac{(a + a + 10)}{2}

By further calculation

\Rightarrow

\frac{(2 a + 10)}{2}

\Rightarrow

2a+10=10

\Rightarrow

2a = 0

\Rightarrow

a = 0
So, first class interval is 0-10.
Continuous grouped frequency table is

Mid point	Class interval	Frequency
5	0-10	4
15	10-20	8
25	20-30	13
35	30-40	12
45	40-50	6

Therefore, from above table we can see that size of class interval is

10

.
Hence, the correct option is 4.

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