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For a satellite escape velocity is $11 {kms}^{- 1}$ . If the satellite is launched at an angle of $60 °$ with a vertical then escape velocity will be

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\frac{11}{\sqrt{3}} {kms}^{- 1}

11 {kms}^{- 1}

11 \sqrt{3} {kms}^{- 1}

33 {kms}^{- 1}

answer is A.

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Detailed Solution

V escape velocity does not depends on the launching angle.

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