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For $0 < θ < \frac{π}{2},$ if the eccentricity of the hyperbola $x^{2} - y^{2} \cos e c^{2} θ = 5$ is $\sqrt{7}$ times eccentricity of the ellipse $x^{2} \cos e c^{2} θ + y^{2} = 5$ , then the value of $θ$ is

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$\frac{π}{3}$

$\frac{π}{4}$

$\frac{π}{6}$

$\frac{5 π}{12}$

answer is B.

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$\sqrt{1 + \sin^{2} θ} = \sqrt{7} \cos θ$

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