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For 109% labeled oleum if the number of moles of $H_{2} S O_{4}$ and free $S O_{3}$ be $x$ and $y$ respectively, then the value of $\frac{x + y}{x - y}$ is

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$1.1$

10.1

0.5

answer is D.

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Detailed Solution

$109 %$ labelled oleum contain $9 g r H_{2} O, 40 g r S o_{3}$ and $60 g r H_{2} S O_{4}$
$40 g r f r e e S O_{3} = 0.5 m o l e s = y$
$60 g r f r e e S O_{4} = 0.61 m o l e s = x$
$\Rightarrow \frac{x + y}{x - y} = 10.09$

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