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Q.

For 2A+B+C Products , rate law is given by rate=k[A][B]2 & rate constant (k) is 2×106M2s1 . Then rate of the reaction become 2×109M2s1 only when

    [A]           [B]            [C]

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a

0.1 M     0.1M      0.2 M

b

0.2 M     0.1 M     0.2 M

c

0.1 M     0.1 M     any value

d

0.2 M     0.2 M     0.1 M

answer is C.

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Detailed Solution

rate=K[A][B]2

[A][B]2=rateK=2×1092×106

                               =103

 if [A]=0.1,[B]=0.1 then

           [A][B]2=0.001

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