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Q.

For $2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$ , $t_{0 .5} = 0 .301 hr$ . When $[H_{2} O_{2}]$ at $t = 0$ is $0 .5 M$ , initial rate is

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a

$2.303 M . h^{- 1}$

b

$1.151 M . h^{- 1}$

c

$4.606 M . h^{- 1}$

d

$0. 301 M . h^{- 1}$

answer is B.

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Detailed Solution

$K = \frac{0 .693}{t_{\frac{1}{2}}} = \frac{0 .693}{0 .301}$

$Rate = K {[H_{2} O_{2}]}^{1}$

$= \frac{0.693}{0.301} \times 0.5$

$= 1 .151 M . h^{- 1}$

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For 2H2O2→2H2O+O2 , t0.5=0.301 hr . When [H2O2] at t=0 is 0.5 M, initial rate is