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For 8g of helium gas (assume ideal behaviour), what is the slope of the straight line in PV vs T graph.

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1 lt.atm. $K^{- 1}$

0.0821 lt.atm. $K^{- 1}$

2lt.atm. $K^{- 1}$

0.1642 lt.atm. $K^{- 1}$

answer is C.

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Detailed Solution

$PV = nRT PV vs T slope = nR = \frac{8}{4} \times 0 .0821 = 2 \times 0 .0821 = 0 .1642$

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