For a 0.072 M NaHSO4 solution , select the incorrect option(s) : (Ka1and Ka2 of H2SO4= ∞ and 1.2x10-2 respectively)

H+=Cα21-α1.2×10-7=7.2×10-2α21-α=6α2+α-1=0α=13pH=-log0.0723=1.62

For a 0.072 M NaHSO4 solution , select the incorrect option(s) : (Ka1and Ka2 of H2SO4= ∞ and 1.2x10-2 respectively)

H+=Cα21-α1.2×10-7=7.2×10-2α21-α=6α2+α-1=0α=13pH=-log0.0723=1.62

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For a 0.072 M NaHSO₄solution , select the incorrect option(s) : ( $K_{a_{1}}$ and $K_{a_{2}}$ of H₂SO₄= $\infty$ and 1.2x10^-2respectively)

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p^H=1.62

pH=7.39

Degree of hydrolysis, h= $\frac{1}{\sqrt{6}}$

h=3.4x10^-6

answer is C, B.

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Detailed Solution

$[H^{+}] = \frac{C α^{2}}{1 - α}$

$1.2 \times 10^{- 7} = \frac{7.2 \times 10^{- 2} α^{2}}{1 - α}$

$= 6 α^{2} + α - 1 = 0$

$α = \frac{1}{3}$

$p H = - \log \frac{0.072}{3} = 1.62$

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For a 0.072 M NaHSO4 solution , select the incorrect option(s) : (Ka1and Ka2 of H2SO4= ∞ and 1.2x10-2 respectively)

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For a 0.072 M NaHSO₄solution , select the incorrect option(s) : ( $K_{a_{1}}$ and $K_{a_{2}}$ of H₂SO₄= $\infty$ and 1.2x10^-2respectively)