Q.

For a 3S-orbital value of ψ  is given by following relation ψ3s=193(1a0)3/2(66σ+σ2)eσ/2   where σ=2r.Z3a0  . 
What is the maximum Radial distance of node from nucleus
 

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a

(3+3)a0Z

b

a0Z

c

32(3+3)a0Z

d

2a0Z

answer is C.

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Detailed Solution

ψ2=0(or)ψ=0 66σ+σ2=0 σ=3±3

For maximum distance  r=32(3+3)a0Z

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