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For $A + B \to_{}^{} C + D, Δ H = - 20 {kJ mol}^{- 1}$ the activation energy of the forward reaction is $85 {kJ mol}^{- 1}$ . The activation energy for backward reaction is _______ ${kJ mol}^{- 1}$

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105

answer is A.

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Detailed Solution

$\begin{aligned} Δ H = E_{a (b)} - E_{a (f)} \\ 20 = E_{a (b)} - 85 \\ E_{a b} = 85 + 20 = 105 kJ / mol \end{aligned}$

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