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For a biased die the probabilities for different faces to turn up are given below.
Face 1 2 3 4 5 6
Probability 0.1 0.32 0.21 0.15 0.05 0.17
The die is tossed and you are told that either face 1 or 2 has turned up. Then the probability that it is face 1 is

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$\frac{5}{21}$

$\frac{6}{23}$

$\frac{5}{23}$

$\frac{16}{21}$

answer is A.

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Detailed Solution

A=face rule 1

B=face value 1 or 2

$P (\frac{A}{B}) = \frac{P (A \cap B)}{P (B)} = \frac{0.1}{0.1 + 0.32} = \frac{10}{42} = \frac{5}{21}$

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