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Q.

For a body angular velocity ω=i^2j^+3k^ and radius vector is r=i^+j^+k^ then its velocity is :

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a

5i^+2j^+3k^

b

5i^+2j^3k^

c

5i^2j^+3k^

d

5i^2j^3k^

answer is A.

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Detailed Solution

v=ω×r=i^j^k^123111=i^(23)j^(13)+k^(1+2)=5i^+2j^+3k^

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