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Q.

For a body in a uniformly accelerated motion, the distance of the body from a reference point at time ‘t’ is given by $x = a t + b t^{2} + c$ where a, b, c are constants. The dimensions of ‘c’ are the same as those of

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a

at

b

$\frac{a^{2}}{b}$

c

x

d

$b t^{2}$

answer is A, B, C.

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Detailed Solution

$x = a t + b t^{2} + c x - d i s \tan c e, t - t i m e x = c \Rightarrow c = m b t^{2} = x x = a t \Rightarrow c = a t c = b t^{2}$

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For a body in a uniformly accelerated motion, the distance of the body from a reference point at time ‘t’ is given by x=at+bt2+c where a, b, c are constants. The dimensions of ‘c’ are the same as those of