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Q.

For a body in S.H.M the velocity is given by the relation v=144−16x2m/sec.The maximum acceleration is

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a

12 m/sec2

b

16 m/sec2

c

36 m/sec2

d

48 m/sec2

answer is D.

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Detailed Solution

v=144−16x2=9×16−16x2v=432−x2=wA2−x2w=4rad/sec;A=3mamax=ω2A=(4)23=48m/s2

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