For a body travelling with uniform acceleration its final velocity (V) is $v = \sqrt{16 - 7 x}$ , where x is the distance travelled by the body. Then its initial velocity and acceleration are

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$8 {ms}^{- 1}, - 4 {ms}^{- 2}$

$8 {ms}^{- 1}, 4 {ms}^{- 2}$

$4 {ms}^{- 1}, 3.5 {ms}^{- 2}$

$4 {ms}^{- 1}, - 3.5 {ms}^{- 2}$

answer is B.

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Detailed Solution

$v^{2} = 16 - 7x$

$v^{2} - 16 = - 7x \Rightarrow v^{2} - 4^{2} = 2 (\frac{- 7}{2}) x$ .....(1)

Comparing eq(1) with $v^{2} - u^{2} = 2 as$

$∴ u = 4 {ms}^{- 1} and a = \frac{- 7x}{2} = - 3.5 {ms}^{- 2}$

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