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For a cell, a graph is plotted between the potential difference V across the terminals of the cell and the current drawn from the cell. The emf and the internal resistance of the cell are E and r, respectively. Then

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$E = 2 V, r = 0.5 Ω$

$E = 2 V, r = 0.4 Ω$

$E = 4 V, r = 0.5 Ω$

$E 4 V, r = 0.4 Ω$

answer is B.

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Detailed Solution

V=E= 2 volts, E/r = 5 amp

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