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Q.

For a cell involving one electron, E°cell =0.59 V at 298 K, the equilibrium constant for the cell reaction is

 [Given that 2.303RT¯=0.059 V atT=298 K ]

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a

1.0×1030

b

1.0×105

c

1.0×1010

d

1.0×102

answer is D.

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Detailed Solution

According to Nernst equation, Ecell=Ecell0.059nlogQc 

At equilibrium Ecell=0,Qc=Kc

Ecell=0.059nlogKc0.59=0.0591logKc

Kc=antilog 10Kc=1×1010

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