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Q.

For a cell reaction involving a two electron changes the standard EMF, of the cell is found to be 0.295 v at $25^{\circ} C .$ At the same
temperature equilibrium constant will be

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a

$29.5 \times 10^{- 2}$

b

$1 \times 10^{10}$

c

$10$

answer is B.

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Detailed Solution

$E^{0} = \frac{0.059}{n} \log k_{c} \Rightarrow K_{c} = 10^{10}$

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