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Q.

For a certain metal. Incident frequency v is five times of threshold frequency  vo and maximum speed of coming out photoelectrons is 8 x106 m/s . If v=2v0, the maximum speed of photoelectrons will be

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a

4×106m/s

b

6×106m/s

c

3×106m/s

d

1×106m/s

answer is A.

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Detailed Solution

K=12mVV2=hv−hvoV2∝v−voV1V2=5vo−vo2vo−vo=2V2=V12=8×1062=4×106m/s

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