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For a certain radioactive substance, it is observed that after 4 h, only 6.25% of original sample is left undecayed. Then after a further 4 h, the amount of the original substance left undecayed will be

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0.62%

2.15%

0.39%

4.25%

answer is C.

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Detailed Solution

$e v e r y f o u r h o u r s i t b e c o m e s 6.25 % o f o r i g i n i a l s o a n o t h e r f o u r h o u r s i t w i l l b e c o m e 6.25 % o f 6.25 \frac{6.25}{100} \times 6.25 = 0.39 %$

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