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For a certain reaction, ΔH⁰ and ΔS⁰ respectively are 400 KJ & 200 J/mol/K. The process is non-spontaneous at

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2100K

2010K

1990K

2020 K

answer is C.

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Detailed Solution

\begin{array}{l} \Delta {H^o} = T\Delta {S^o}\\\\ T = \frac{{\Delta {H^o}}}{{\Delta {S^o}}} = \frac{{400}}{{0.2}} = 2000K\\\\ T > 2000K\,\,;\,\,Spon\tan eous\\ T < 2000K\,;\,nonspon\tan eous\\ T = 2000K\,;\,equillibrium \end{array}

$∆ G^{0} = ∆ H^{0} - T ∆ S^{0}; ∆ G^{0} = + ve - T (+ ve); ∆ G^{0} will be positive only when T < T_{eq};$

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