For a chemical reaction 2X + Y +Z, the rate of appearance of Z is 0.05 mol L^-1 min^-1. The rate of disappearance of X will be

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$0.1 mol L^{- 1} \min^{- 1}$

$0.25 mol L^{- 1} \min^{- 1}$

$0.05 mol L^{- 1} \min^{- 1}$

$0.05 mol L^{- 1} {hr}^{- 1}$

answer is C.

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Detailed Solution

$\begin{array}{l} 2 X + Y ⟶ Z \\ Rate = \frac{= d [X]}{2 dt} = \frac{- d [Y]}{dt} = \frac{+ d [Z]}{dt} \\ ∴ \frac{- d [X]}{dt} = 2 \times \frac{d [Z]}{dt} = 2 \times 0 .05 = 0 .1 {molL}^{- 1} \min^{- 1} \end{array}$

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