For a chemical reaction, $mA \to xB$ , the rate law is . If the concentration of A is doubled, the reaction rate will be:

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Unchanged

Increases by 8 times

Quadrupled

Doubled

answer is C.

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Detailed Solution

Concept- The rate at which the concentration of any one of the reactants changes determines the rate of any reaction. Since the concentration of its reactants determines the pace of reaction, we know that if we vary the concentration, the rate of reaction will also change.
Now, the rate law is given as

in the question. Additionally, the rate is stated in terms of concentration, which in turn affects the rate of reaction, in the rate law.
Let's thus assume that A has an initial concentration of x.
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But if we increase the concentration of A and double it, then the rate of the reaction will become as:
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Now comparing both the rates of the reaction we would get:
Question Image

As a result of the argument provided above, we may conclude that if the concentration of A is twice, the rate of reaction will also be quadrupled.
Hence, the correct answer is option 3).

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