For a chemical reaction Y2+2Z→product, rate controlling step is Y+12Z→Q. If the concentration of Z is doubled, the rate of reaction will

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For a chemical reaction $Y_{2} + 2 Z \to$ product, rate controlling step is $Y + \frac{1}{2} Z \to Q$ . If the concentration of Z is doubled, the rate of reaction will

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answer is C.

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Detailed Solution

$rate \infty {[Z]}^{\frac{1}{2}}$

$rate \infty {[2]}^{\frac{1}{2}}$

rate incrases by 1.414 times

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