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Q.

For a concentrated solution of a weak electrolyte Ax By, the degree of dissociation is given by

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a

α=Keq/c(xy)

b

α=Keq/cx+y1xyyxx+y

c

α=Keq/cx+y1xxyy1/(x+y)

d

α=Keq/c(x+y)

answer is D.

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Detailed Solution

For a concentrated solution of a weak electrolyte Ax By

                                     AxBy   xAy++yBx- Initial                         C                  0          0 At equilibrium   C-C+    Cxα    Cyα

We have

Keq=Ay+xBxyAxBy=(Cxα)x(Cyα)yC-C()=cx+y1xxyyαx+y      =Cx+y-1(x)x(y)yαx+y1-α(x+y) α<<1      =Cx+y-1(x)x(y)yαx+y1α=KeqCx+y-1(x)x(y)y1x+y 

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