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For a definite amount of gas, pressure and volume are increased to triple of the initial amount. Therefore

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Temperature increased to nine times of its initial value

Temperature increased to thrice of its initial value

Temperature remains unaltered

Temperature reduced to thrice of its initial value

answer is A.

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Detailed Solution

$\frac{PV}{T} = constant \Rightarrow \frac{PV}{T_{1}} = \frac{3 P \times 3 V}{T_{2}}$

$T_{2} = 9 T_{1}$

Temperature increased to nine times of its initial value.

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